Equilibrium Constant and Standard Free Energy Change
What are the ...
Question
What are the value of △G∘ and the equilibrium constant for the formation of NO2 from NO and O2 at 298 K. Given log (1.365×106)=6.14 NO(g)+12O2(g)⇌NO2(g) where △G∘(NO2)=52.0 kJ/mol △G∘(NO)=87.0 kJ/mol △G∘(O2)=0 kJ/mol
A
35 kJ mol−1 and 1.365×106
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B
-35 kJ mol−1 and 1.365×10−6
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C
-350 kJ mol−1 and 1.3×106
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D
-35 kJ mol−1 and 1.365×106
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Solution
The correct option is D -35 kJ mol−1 and 1.365×106 △G∘=△G∘NO2−△G∘NO=(52−87)kJmol−1=−35kJmol−1∵△G0=−2.303RTlogKlogK=−35kJmol−12.303×−8.301JK−1mol−1×298K On solving K=1.365×106