What are the values of - U and - H when 10 dm 3 of Helium at NTP is heated in a cylinder to 100- C- assuming that the gas behaves ideally- -C V -3-2 R A- - U-556-74 J- H-927-9 JB- - U-927-9 J- H-556-74 JC- - U-557-74 J- H-927-9 JD- - U-556-74 J- H-926-9 J

The correct option is A We know that Δ U = nC_VΔ T No of moles of Helium = 10 dm^3/22.4 dm^3 C_V = (3/2)R Δ T = 100 Δ U = 10/22.4 × 3/2 × 8.314 × 100 Δ ...

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Byju's Answer

Standard XII

Chemistry

CFSE Comparison

What are the ...

Question

What are the values of $Δ U$ and $Δ H$ when $10 d m^{3}$ of Helium at NTP is heated in a cylinder to $100^{\circ} C$ , assuming that the gas behaves ideally. ( $C_{V} = \frac{3}{2} R$ )

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Solution

The correct option is A

We know that

$Δ U = n C_{V} Δ T$

No of moles of Helium = $\frac{10 d m^{3}}{22.4 d m^{3}}$

$C_{V} = (\frac{3}{2}) R$

$Δ T = 100$

$Δ U = \frac{10}{22.4} \times \frac{3}{2} \times 8.314 \times 100$

$Δ U = 556.74 J$

Now we know that $Δ H = n . C P . Δ T$

$C_{P} - C_{V} = R$
$C_{P} - \frac{3}{2} R = R$

$C_{P} = \frac{5}{2} R$

$∴ Δ H = \frac{10}{22.4} \times \frac{5}{2} \times 8.314 \times 100$

$∴ Δ H = 927.9 J$

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What are the values of ΔU and ΔH when 10 dm3 of Helium at NTP is heated in a cylinder to 100∘ C, assuming that the gas behaves ideally. (CV = 32 R)

The correct option is A We know that Δ U = nCVΔ T No of moles of Helium = 10 dm322.4dm3 CV = (32)R ΔT = 100 Δ U = 1022.4 × 32 × 8.314 × 100 Δ U = 556.74 J Now we know that Δ H = n.CP.Δ T CP − CV = R CP − 32R = R CP = 52 R ∴ Δ H = 1022.4 × 52 × 8.314 × 100 ∴ Δ H = 927.9 J

What are the values of $Δ U$ and $Δ H$ when $10 d m^{3}$ of Helium at NTP is heated in a cylinder to $100^{\circ} C$ , assuming that the gas behaves ideally. ( $C_{V} = \frac{3}{2} R$ )