What are the values of m and n in the anionic species [V(CO) $_{m}$ ] $^{n -}$ , if it is following Sidgwick E.A.N. rule and having octahedral shape?

m = 4, n = 1

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m = 6, n = 2

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m = 6, n = 1

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none of these

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Solution

The correct option is B m = 6, n = 1
Octahedral shape corresponds to 6 CO ligands.

Hence, $m = 6$

$E A N = 23 + n + 2 \times 6 = 23 + n + 12 = 35 + n = 36$ .

Hence, $n = 1$ .

Thus, the complex is $[V (C O)_{6}]^{-}$ .

Therefore, the option is C.

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