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Question

What are the values of the self-induced emf in the circuit of the previous problem at the times indicated therein?

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Solution

Given:
Self-inductance, L = 1 H
For an inductor of self-inductance L, the emf induced is given by
e = Ldidt

(a) At t = 100 ms,
didt = 0.27 A/s
∴ Induced emf, e = Ldidt = 1 × 0.27 = 0.27 V

(b) At t = 200 ms,
didt=0.036 A/s
∴ Induced emf = Ldidt = 1 × 0.036 = 0.036 V

(c) At t = 1 s,
didt = 4.1 × 10−9 A/s
∴ Induced emf = Ldidt = 4.1 × 10−9 V

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