What are $Y$ and $Z$ in the following reaction sequence ?
$C H_{2} = C H B r N a N H_{2} - ---- \to Y H g^{2 +} / H^{⨁} - ----- \to H_{2} O; 333 K Z$

Y -

ethyne,

Z -

acetic acid

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Y -

ethyne,

Z -

ethanal

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Y -

ethylamine,

Z -

ethanal

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Y -

ethane,

Z -

ethanol

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Solution

The correct option is B $Y -$ ethyne, $Z -$ ethanal

$C H_{2} = C H B r N a N H_{2} - ---- \to H - C \equiv C - H H g^{2 +} / H^{⨁} - ----- \to H_{2} O; 333 K C H_{3} C H O$

$N a N H_{2} \to N a^{+} + {N H_{2}}^{-}$

$C H_{2} = C H B r + {N H_{2}}^{-} \to H - C \equiv C - H + N H_{3}$

then the acetylene undergo the further reaction as given in figure.

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