What coefficient is needed for $H_{2} O$ to balance the following equation?
$C_{3} H_{8} + O_{2} \to {C O}_{2} + H_{2} O$

4

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Solution

The correct option is A $4$
$C_{3} H_{8} + O_{2} ⟶ C O_{2} + H_{2} O$
$⟹$ Blance $C$ first by writing $3$ before $C O_{2} .$
$⟹$ Balance $H$ by writing $4$ before $H_{2} O .$
There are $10$ Oxygen atoms right side, keep $5$ before $O_{2}$ to balance Oxygen atom.

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