What coefficients are required to balance the following equation?
${F e}_{2} {({S O}_{4})}_{3} + A l {P O}_{4} \to F e {P O}_{4} + {A l}_{2} {({S O}_{4})}_{3}$

1, 1, 1, 1

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2, 4, 4, 2

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3, 4, 4, 3

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3, 4, 2, 1

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Solution

The correct option is C $2, 4, 4, 2$
$F e_{2} (S O_{4})_{3} + A l P O_{4} \to F e P O_{4} + A l_{2} (S O_{4})_{3}$
In products there are $2 m o l e s$ of Aluminium. So add $2 m o l e s$ of $A l P O_{4}$
$\Rightarrow F e_{2} (S O_{4})_{3} + 2 A l P O_{4} \to F e P O_{4} + A l_{2} (S O_{4})_{3}$
In reactants there are $2 m o l e s$ of iron. So add $2 m o l e s$ of $F e P O_{4}$
$\Rightarrow F e_{2} (S O_{4})_{3} + 2 A l P O_{4} \to 2 F e P O_{4} + A l_{2} (S O_{4})_{3}$
So, the coefficients are 1, 2, 2, 1 or 2, 4, 4 ,2.

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