What concentration of CO 2 be in equilibrium with 2-5- 10 -2 mol L -1 of CO at 100C for the reaction- FeOs-COg- Fes- CO 2 g- K C -5-0

The correct option is B CO _ 2 at equilibrium=12.5× 10 ^ 2 mol L ^ 1 As we know, FeO(s)+CO(g)⇌ Fe(s)+ CO _ 2 (g) For this reaction, K _ C = ...

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Standard XII

Chemistry

Reaction Quotient

What concentr...

Question

What concentration of ${C O}_{2}$ be in equilibrium with $2.5 \times 10^{- 2} {m o l L}^{- 1}$ of CO at 100C for the reaction:
$F e O (s) + C O (g) ⇌ F e (s) + {C O}_{2} (g); K_{C} = 5.0$

{C O}_{2} a t e q u i l i b r i u m = 1.5 \times 10^{- 2} m o l L^{- 1}

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{C O}_{2} a t e q u i l i b r i u m = 62.5 \times 10^{- 2} m o l L^{- 1}

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{C O}_{2} a t e q u i l i b r i u m = 2.5 \times 10^{- 2} m o l L^{- 1}

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{C O}_{2} a t e q u i l i b r i u m = 12.5 \times 10^{- 2} m o l L^{- 1}

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Solution

The correct option is B ${C O}_{2} a t e q u i l i b r i u m = 12.5 \times 10^{- 2} m o l L^{- 1}$
As we know,
$F e O (s) + C O (g) ⇌ F e (s) + {C O}_{2} (g)$
For this reaction,
$K_{C} = \frac{[{C O}_{2}]}{[C O]}$
$∴ 5 = \frac{[{C O}_{2}]}{2.5 \times 10^{- 2}}$
$∴ {C O}_{2} a t e q u i l i b r i u m = 2.5 \times 10^{- 2} \times 5 = 12.5 \times 10^{- 2} m o l L^{- 1}$

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What concentration of CO2 be in equilibrium with 2.5×10−2molL−1 of CO at 100C for the reaction:FeO(s)+CO(g)⇌Fe(s)+CO2(g);KC=5.0

The correct option is B CO2atequilibrium=12.5×10−2molL−1As we know,FeO(s)+CO(g)⇌Fe(s)+CO2(g)For this reaction,KC=[CO2][CO]∴5=[CO2]2.5×10−2∴CO2atequilibrium=2.5×10−2×5=12.5×10−2molL−1

What concentration of ${C O}_{2}$ be in equilibrium with $2.5 \times 10^{- 2} {m o l L}^{- 1}$ of CO at 100C for the reaction:
$F e O (s) + C O (g) ⇌ F e (s) + {C O}_{2} (g); K_{C} = 5.0$