What conclusions can be drawn from the following reactions- H - 2-4-5 eV- -rightarrow H - H H -13-6 eV -rightarrow p - e -1A- It is more difficult to break up an H 2 molecule than it is to break up a hydrogen atomB- It is easier to break up an H 2 molecule than it to break up a hydrogen atomC- The average energy of formation of H and p -are the sameD- Electron and proton attraction in an H 2 molecule as well as an H atom are the same

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Standard XII

Chemistry

Sigma Bond and Pi Bond

What conclusi...

Question

What conclusions can be drawn from the following reactions?
$H_{2} + 4.5 e V \to H + H H + 13.6 e V \to p^{+} + e^{-}$

It is more difficult to break up an

H_{2}

molecule than it is to break up a hydrogen atom

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It is easier to break up an

H_{2}

molecule than it to break up a hydrogen atom

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The average energy of formation of

H

and

p^{+}

are the same

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Electron and proton attraction in an

H_{2}

molecule as well as an

H

atom are the same

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Solution

The correct option is B It is easier to break up an $H_{2}$ molecule than it to break up a hydrogen atom
The energy required to break up the hydrogen atom is greater than that required to break up the $H_{2}$ molecule, as the electron in $H$ atom is held by strong forces of attraction.

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Similar questions

Q. What conclusions can be drawn from the following reactions?

H_{2} + 4.5 e V \to H + H H + 13.6 e V \to p^{+} + e^{-}

Q. An element undergoes a reaction as shown:

X + 2 e^{-} \to X^{2 -}

, energy released

= 30.87 e V / a t o m

. If the energy released , is used to dissociate

4 g m s

H_{2}

molecules, equally into

H^{+}

and

H^{*}

, where

H^{*}

is excited state of

H

atoms where the electron travels in orbit whose circumference equal to four times its de Broglie's wavelength. Determine the least moles of

X

that would be required:
Given

I . E o f H = 13.6 e V / a t o m

, bond energy of

H_{2} = 4.526 e V / m o l e c u l e

Q. The quantum of ________ assets as well as its break-up is an aspect affected by finance.

Q. If one of the two electrons of a

H_{2}

molecule is removed, we get a hydrogen molecular ion

H_{2}^{+}

. In the ground state of an

H_{2}^{+}

, the two protons are separated by roughly

1.5 ˚ A

, and the electron is roughly

1 ˚ A

from each proton. Determine the potential energy of the system. Specify your choice of the zero of potential energy.

Q. Using the Heisenberg uncertainty principle arrange the following particles in the order of increasing lowest energy possible.

(I)

an electron in

H_{2}

molecule

(I I)

H

atom in a

H_{2}

molecule

(I I I)

a proton in the carbon nucleus

(I V)

H_{2}

molecule within a nanotube

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What conclusions can be drawn from the following reactions? H2+4.5eV→H+HH+13.6eV→p++e−

The correct option is B It is easier to break up an H2 molecule than it to break up a hydrogen atomThe energy required to break up the hydrogen atom is greater than that required to break up the H2 molecule, as the electron in H atom is held by strong forces of attraction.

What conclusions can be drawn from the following reactions?
$H_{2} + 4.5 e V \to H + H H + 13.6 e V \to p^{+} + e^{-}$

The correct option is B It is easier to break up an $H_{2}$ molecule than it to break up a hydrogen atom
The energy required to break up the hydrogen atom is greater than that required to break up the $H_{2}$ molecule, as the electron in $H$ atom is held by strong forces of attraction.