Question

What could be the value of $Q$ in the following equation?
$4P8+8Q3+7R8=2079$

Where $4P8,8Q3,7R8$ are three digit numbers with ten's digit as $P,Q,R$ respectively.

• A. Between $0\le Q\le 9$
• B. More than or equal to $7$
• C. Less than $6$
• D. Between $0\le Q\le 11$

Answer 1

Answer: (A), (B), (C)

The correct options are
A Between $0\le Q\le 9$
B More than or equal to $7$
C Less than $6$

Given equation is
$4P8+8Q3+7R8=2079$
Sum of unit digits in $(4P8+8Q3+7R8)$ is 19, so 1 will be carried to ten's place.
4 P 8
8 Q 3
7 R 8
------------
2 0 7 9
$\therefore 1+P+Q+R=17$
Also $0+9+7=16$
Hence maximum value of $Q=9$