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Question

What could be the value of Q in the following equation?
4P8+8Q3+7R8=2079

Where 4P8,8Q3,7R8 are three digit numbers with ten's digit as P,Q,R respectively.


A
Between 0Q9
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B
More than or equal to 7
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C
Less than 6
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D
Between 0Q11
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Solution

The correct options are
A Between 0Q9
B More than or equal to 7
C Less than 6
Given equation is
4P8+8Q3+7R8=2079
Sum of unit digits in (4P8+8Q3+7R8) is 19, so 1 will be carried to ten's place.
4 P 8
8 Q 3
7 R 8
------------
2 0 7 9
1+P+Q+R=17
Also 0+9+7=16
Hence maximum value of Q=9

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