MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Magnetic Field Due to a Straight Current Carrying Conductor

What current ...

Question

What current must flow in a circular coil of 20 loops of radius 40 cm to produce a magnetic field of 3π * 10^-2T at its centre?

Open in App

Solution

We use the BIOT SAVART's law for finding the magnetic field B at the center of circular coil.

R= 0.40 m
N = loops = 20
Given B = 3π× 10-² T.

B = μ0 N I/ (2 R)
I = 2 B R /(μ0 N)
I = 23π×10-² 0.40 / (4π10^-7*20) A
I = 3000A.

Suggest Corrections

thumbs-up

0

Similar questions

Q. Due to the flow of current in a circular loop of radius

R

, the magnetic field produced at the centre of the loop is

B

. The magnetic moment of the loop is:-

Q. Due to the flow of current in a circular loop of radius R, the magnetic field produced at the centre of the loop is B. The manetic moment of the loop is:-

Q. A current-carrying circular coil of 100 turns and radius 5.0 cm produces a magnetic field of 6.0 × 10⁻⁵ T at its centre. Find the value of the current.

Q. A current flows in a circular arc of wire whose radius is

R

, which subtends an angle

\frac{3 π}{2}

radian at its centre. The magnetic field

B

at the centre is

i A

flows in a circular arc of wire whose radius is

R

and it subtends an angle

\frac{3 π}{2} radian

at its centre. The magnetic field at the centre is

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Magnetic Field Due to a Current Carrying Conductor

PHYSICS

Watch in App

explore_more_icon

Explore more

Magnetic Field Due to a Straight Current Carrying Conductor

Standard X Physics

Join BYJU'S Learning Program

CrossIcon