Question

What current strength in amperes will be required to liberate 10 gm of iodine from potassium iodide solution in one hour? (Equivalent mass of Iodine is 127).

Answer 1

127 g iodine (1 g equivalent ) is liberated by =96.500
coulomb
$\therefore$ 10 g of iodine is liberated by $\frac{96,500}{127}\times 10$ Coulomb
Let the current strength be I
Time in Second $=1\times 60\times 60$
Quantity of electricity $Q=I\times timeinseconds$
Current strength $I=\frac{Q}{t}=\frac{96,500\times 10}{127\times 60\times 60}$
$=2.11ampere$