Question

What current strength would be required to produce hydrogen gas at the rate of $1.12c{m}^3{s}^{-1}$(STP) by the electrolysis of aqueous NaCl solution with 96.5% current efficiency ?

• A. 9.65 A
• B. 9.31 A
• C. 10.00 A
• D. 0.10 A

Answer 1

The correct option is C

10.00 A

$Cathode:2H_{2}O+2e^{-}\to H_2+2O{H}^{-};$
z for $H_2$ in terms of $c{m}^3\left(STP\right)$
$=\frac{22400}{2\times 96500}=\frac{112}{965}c{m}^3{c}^{-1}Hence,V\left(H_2\right)=1.12c{m}^3=zit\times \frac{96.5}{100}=\frac{112}{965}\times i\times l\times \frac{96.5}{100}\Rightarrow i=10A$