MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Ohm's Law

what current ...

Question

what current will a aluminium wire draw of length 1m and area of cross section 1mm² from a 240V battery?

Open in App

Solution

$r e s i s t i v i t y o f a l u m i n i u m; ρ = 10^{14} o h m m e t e r R = \frac{ρ L}{A} = \frac{10^{14} \times 1}{10^{- 6}} = 10^{8} o h m I = \frac{V}{R} = \frac{240}{10^{8}} = 2.4 \times 10^{- 6} A$

Suggest Corrections

thumbs-up

0

Similar questions

What will happen when we do wiring of a house with 2.5mm² instead of 1mm²cross section area of wire. Is extra current used or current is wasted?

Q. A wire 50 cm long and

1 m m^{2}

in cross-section carries a current of 4 A when connected to a 2 V battery. The resistivity of the wire is

Q. A nichrome wire

50 c m

1 m m^{2}

cross-section carries a current of

4 A

when connected to a

2 V

battery. The resistivity of nichrome wire in ohm-meter is

Q. A conducting wire of length

l

, area of cross-section

A

and electrical resistivity

ρ

is connected between the terminals of a battery. A potential difference

V

is developed between its ends, causing an electric current. If the length of the wire is doubled and the area of cross-section is halved, the resultant current would be:

The work done in increasing the length of a one metre long wire of cross-sectional area $1 m m^{2}$ through 1 mm will be

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Intrinsic Property_Tackle

PHYSICS

Watch in App

explore_more_icon

Explore more

Standard X Physics

Join BYJU'S Learning Program

CrossIcon