Question

What current will flow through the $2k\Omega$ resistor in the circuit shown in the figure?

• A. $3mA$
• B. $6mA$
• C. $12mA$
• D. $36mA$

Answer 1

The correct option is A $3mA$

Applying Kirchoff's loop law along $ABCDEF-$

$E=(2I_1+4I_1+6I)\times {10}^3$

$⟹6(I_1+I)\times {10}^3=72V$

$⟹I_1+I=12mA$

Along loop $BCDE-$

$2I_1+4I_1-3(I-I_1)=0$

$⟹9I_1=3I$

$⟹I=3I_1$

And, $I+I_1=12mA$

$⟹3I_1+I_1=12mA$

$⟹I_1=3mA$=current in $2k\Omega$ resistance

Answer-(A)