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Relative Lowering of Vapour Pressure

What does it ...

Question

What does it means?
$0.49 %$ w/v $H_{2} {S O}_{4}$ solution .

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Solution

Solution:-
$0.49 % w / v$ means $0.49 g$ of $H_{2} S O_{4}$ is present in $100 m L$ of solution.

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Q. Calculate normality of 2.1%(w/V)

H_{2} {S O}_{4}

15 %

H_{2} {S O}_{4}

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then Calculate its molarity.

Q. Find the molality of the solution having

93

H_{2} {S O}_{4}

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) having density

1.84 g m L^{- 1}

Q. Calculate the molality of

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Q. The molarity of 15% (w/w) solution of

H_{2} {S O}_{4}

of density 1.1 g/cc is:

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