What does the area under velocity– time graph give?

Acceleration

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Displacement

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Average speed

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Average velocity

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Solution

The correct option is B Displacement
The area under a velocity-time graph gives the displacement of the object.

In the graph shown, the area under the curve is shaded in blue, and is equal to the displacement of the object.
So, displacement $(s)$ is given by:
$s = A r (A B C D E)$
$s = A r (A B C D) + A r (A D E)$

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What does Area under POSITION-TIME graph give?

Just curious to know, sorry if it's silly.

The area enclosed under the velocity-time graph gives acceleration.