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Byju's Answer

Standard IX

Chemistry

Bohr's Model of an Atom

What electron...

Question

What electronic transition in $L i^{+ 2}$ produces the radiation of the same wave length as the first Line in the Lyman series of hydrogen?

n₂=4 to n₁=2

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n₂=9 to n₁=6

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n₂=9 to n₁=3

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n₂=6 to n₁=3

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Solution

The correct option is D
n₂=6 to n₁=3

Wavelength is same

$\to ¯ ¯ ¯ v$ is also same

$R [\frac{1}{2^{2}} - \frac{1}{2^{2}}]$ = $R 3^{2} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]$

$\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \frac{1}{3^{2}} \frac{1}{6^{2}}$

$\to n_{1} = 3$ $n_{2} = 6$

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What electronic transition in Li+2 produces the radiation of the same wave length as the first Line in the Lyman series of hydrogen?

The correct option is D n2=6 to n1=3 Wavelength is same → ¯¯¯v is also same R[122 − 122] = R32[1n21 − 1n22] 1n21 − 1n22132162 → n1 = 3 n2 = 6

What electronic transition in $L i^{+ 2}$ produces the radiation of the same wave length as the first Line in the Lyman series of hydrogen?

The correct option is D
n₂=6 to n₁=3

Wavelength is same

$\to ¯ ¯ ¯ v$ is also same

$R [\frac{1}{2^{2}} - \frac{1}{2^{2}}]$ = $R 3^{2} [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}]$

$\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}} \frac{1}{3^{2}} \frac{1}{6^{2}}$

$\to n_{1} = 3$ $n_{2} = 6$