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Question

What electronic transition in the He+ ion would emit the radiation of the same wavelength as that of the first Lyman transition of hydrogen atom ?

A
21
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B
42
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C
31
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D
24
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Solution

The correct option is B 42
For the first Lyman transition for hydrogen,
1λ=RZ2(1n211n22)=R12(112122)=3R4
Since, wavelength of the radiation emitted in electronic transition in He+ is the same as for hydrogen,
1λHe+=R.22(1n211n22)=3R4

Hence, n1 and n2 have to be 2 and 4 respectively as,
1λ=4R(122142)=3R4

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