What electronic transition in the He+ spectrum would have the same wavelength as the first Lymen transition of hydrogen:-
A
n = 4 to n = 2
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B
n = 1 to n = 4
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C
n = 4 to n = 3
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D
n = 3 to n = 4
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Solution
The correct option is A n = 4 to n = 2 The first Lymen transition of hydrogen 1λH=R(1)2[112−122] & For He+, 1λ+He=R(2)2[1n21−1n22] But λH=λ+He [as given in question] ∴ From above equations n1=2&n2=4