Question

What force will produce a moment of force$4.5N-m$, if the perpendicular distance between the force and the turning point is$20cm$?

Answer 1

Step 1-

Given Data;

Moment of a force, M.F=$4.5N-m$

Force, F=?

Perpendicular distance, d= $20cm$=$20\times {10}^{-2}m$

Step 2-

Formula used;

$Momentofforce=Force\times perpendiculardis\tan cebetweentheforceandturningpoint$

$M.F=F\times d$

Step 3-

Calculation;

$$\begin{gathered} M.F=F\times d \\ 4.5Nm=F\times 20\times {10}^{-2}m \\ 4.5=F\times 20\times {10}^{-2} \\ F=\frac{4.5}{20\times {10}^{-2}} \\ =\frac{45\times {10}^2}{20\times 10} \\ =\frac{45}{2} \\ =22.5 \\ F=22.5N \end{gathered}$$

Hence, force is $22.5Newton.$