What fraction is $270 g$ of $3 k g$ .

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Solution

We have
$3 k g = 3 \times 1000 g m = 3000 g m$
$\frac{270 g m}{3000 g m} = \frac{9}{100}$
so, $270 g m$ is $\frac{9}{100}$ of $3 k g$

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