Question

What fraction must be subtracted from the sum of $\frac{1}{4}and\frac{1}{6}$ to have an average of $\frac{1}{12}$ of all the three fractions?

• A. $\frac{1}{2}$
• B. $\frac{1}{3}$
• C. $\frac{1}{4}$
• D. $\frac{1}{6}$
• E. None of these

Answer 1

The correct option is D $\frac{1}{6}$

Here,
Required fraction
$=\frac{1}{4}+\frac{1}{6}-3\times \frac{1}{12}=\frac{1}{4}+\frac{1}{6}-\frac{1}{4}=\frac{1}{6}$