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Henderson Hassleback Equation

What fraction...

Question

What fraction of an indicator $H I n$ is in the basic form at a $p H$ of $6$ if $p K_{a}$ of the indicator is $5$ ?

\frac{1}{2}

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\frac{1}{11}

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\frac{10}{11}

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\frac{1}{10}

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Solution

The correct option is D $\frac{1}{10}$
$p H = p H I n + log \frac{{I n}^{-}}{{H I}_{A}}$
$6 = 5 + log \frac{{I n}^{-}}{H I n}$
$\frac{{I n}^{-}}{H I n} = \frac{1}{10}$

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