What happens if $N a H C O_{3}$ is added to aqueous $Z n S O_{4}$ solution ?

Clear Solution formed (transparent)

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Precipitated formed

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Soluble solution formed

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None of these

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Solution

The correct option is B Precipitated formed

$Z n S O_{4}$ + $2 N a H C O_{3}$ $⟶$ $Z n C O_{3}$ + $N a_{2} S O_{4}$ + $H_{2} O$ + $C O_{2}$

Hence, $Z n C O_{3}$ is formed as precipitate.
So, option B is correct

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