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Question
What happens to gravitational force when the masses of two object are tripled and the distance between rhem are also tripled
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Solution
F'=(GM1M2)/d^2
F'=(G*3M1*3M2)/(3d)^2
F'=(9GM1M2)/9d^2
F'=9/9F
(because F=Gm1m2/d2)
Therefore,
F'=F
Thus, the gravitational force between the objects would remain same
F'=(G*3M1*3M2)/(3d)^2
F'=(9GM1M2)/9d^2
F'=9/9F
(because F=Gm1m2/d2)
Therefore,
F'=F
Thus, the gravitational force between the objects would remain same
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