What happens to the area of a rectangle if its length is doubled, breadth remains the same?

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Solution

Step 1:
Area of rectangle $= l e n g t h \times b r e a d t h$
Let initial length be $x u n i t$ and breadth $y u n i t$
Initial area $= x y s q u a r e u n i t$
Step 2:
New length when doubled is $2 x u n i t$ and breadth same as $y u n i t$
New area $= 2 x y s q u a r e u n i t$
Step 3:
Impact on area of rectangle $= \frac{N e w a r e a}{I n i t i a l a r e a} = \frac{2 x y}{x y} = 2 t i m e s$
Hence, area of rectangle become $2 t i m e s$ when length is doubled and breadth remains same.

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