Question

What happens to the area of triangle when its base is doubled, height is halved?

Answer 1

Let original base, height $=b,h$ and new $=2b,\frac{h}{2}$

$\Rightarrow$ Original area, $A=\frac{1}{2}bh$ and new $A^{\prime }=\frac{1}{2}\left(2b\right)\left(\frac{h}{2}\right)$

$=\frac{1}{2}bh$

$\Rightarrow A=A^{\prime }$.