Question

What happens to the force experienced by a current carrying conductor in a uniform magnetic field, when placed perpendicular to the magnetic field?

Answer 1

Whenever a current carrying conductor is placed in a uniform magnetic field. It will experience a magnetic force. However, the magnetic force depends on various parameters. it is given by

$F=IlB\sin \theta$

where $I$ is the current in the conductor, $l$ is the length of conductor, $B$ is the magnitude of magnitude of magnetic field, and $\theta$ is the angle between conductor ($l$) and magnetic field.

Hence the magnetic force depends on the four things:

Amount of current
Strength of Magnetic field
Length of the wire which remain in magnetic field and
Angle between the current carrying conductor and magnetic field.

In the question conductor is placed perpendicular to the magnetic field i.e $\theta$ = ${90}^o$ that means $\sin \theta =1$ that is maximum possible value of $\sin \theta$.

When the current carrying wire is placed perpendicular to the magnetic field then magnetic force acting on the conductor is maximum i.e $F=IlB$ .