What happens to the potential energy of an object, if its mass is doubled and its lifted height is halved from its initial state?
A
Becomes quadruple
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B
Becomes half
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C
Becomes double
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D
Remains same
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Solution
The correct option is D
Remains same
Let the mass and height of the object is m and h respectively.
Therefore its potential energy is mgh.
If its mass is doubled and height is halved from the initial state then new potential energy will be (2m×g×h2)=mgh
Hence, in this also the potential energy remains same.