Question

What happens when 2-methyl-2-butene is treated with alk. KMnO₄ at 373K.

Answer 1

Hi,

2-Methylbut-2-ene and the aqueous alkaline solution of potassium permanganate (Baeyer's reagent) at room temperature results in the formation of 2-Methybutane-1,2-diol. (cis-hydroxylation).

${\mathrm{CH}}_3\mathrm{C}({\mathrm{CH}}_3)={\mathrm{CH}}_2{\mathrm{CH}}_3\stackrel{\mathrm{alkaline}{\mathrm{KMnO}}_4}{\to }{\mathrm{CH}}_3\mathrm{C}({\mathrm{CH}}_3)(\mathrm{OH}\left){\mathrm{CH}}_2\right(\mathrm{OH}){\mathrm{CH}}_3$

Regards