What happens when a solution of pottasium chromate is treated with an excess of dilute nitric acid?
A
Cr3+ and Cr2O2−7 are formed
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B
Cr2O2−7 and H2O are formed
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C
CrO2−4 is reduced to +3 state of Cr
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D
CrO2−4 is reduced to 0 state of Cr
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Solution
The correct option is BCr2O2−7 and H2O are formed When a solution of potassium chromate is treated with an excess of dilute nitric acid, dichromate and water are formed. 2CrO2−4+2H+⟶Cr2O2−7+H2OYellowOrange