Question

What happens when diborane reacts with Lewis bases?

• A. It forms boron trihydride $\left(B{H}_3\right)$ due to cleavage.
• B. It undergoes cleavage to give borane adduct $B{H}_{3}L$ (where, L = Lewis base).
• C. It oxidises to give $B_2{O}_3$.
• D. It does not react with Lewis bases.

Answer 1

The correct option is B It undergoes cleavage to give borane adduct $B{H}_{3}L$ (where, L = Lewis base).

Answer:- (B) It undergoe cleavage to give borane adduct $B{H}_{3}L$ ( where, L = Lewis base).

Reaction of diborane with Lewis base $\to$

$B_2{H}_6+2L\underset{(L=Lewisbase)}{\overset{[L=N{H}_3,P{H}_3,etc.]}{\to }}\underset{\left(Adduct\right)}{2B{H}_3.L}$