Question

What happens when ethanoic acid reacts with sodium carbonate. Give a balanced chemical equation and write the name of the reactants and products.

Answer 1

In the given compound Ethanoic acid $\left({\mathrm{CH}}_3\mathrm{COOH}\right)$, a carboxyl group is present which represents the carboxylic functional group is present in the compound.

Ethanoic acid reacts with Sodium carbonate $\left({\mathrm{Na}}_2{\mathrm{CO}}_3\right)$ to form the Carbon dioxide $\left({\mathrm{CO}}_2\right)$ gas with effervescence.

The balanced chemical equation of the reaction of Ethanoic acid with Sodium carbonate is written as:

$$\begin{gathered} 2{\mathrm{CH}}_3\mathrm{COOH}+{\mathrm{Na}}_2{\mathrm{CO}}_3\to 2{\mathrm{CH}}_3\mathrm{COONa}+{\mathrm{CO}}_2+{\mathrm{H}}_2\mathrm{O} \\ (\mathrm{Ethanoic}(\mathrm{Sodium}(\mathrm{Sodium}\mathrm{acetate})(\mathrm{Carbon}(\mathrm{water}) \\ \mathrm{acid})\mathrm{carbonate})\mathrm{dioxide}) \end{gathered}$$

The reactants in the chemical equation are Ethanoic acid and Sodium carbonate whereas the products formed in the chemical equation are Sodium acetate, Water, and Carbon dioxide gas.