What happens when
i) White phosphorous is heated with concentrated $N a O H$ solution in an inert atmosphere of $C O_{2}$ .
ii) $X e F_{6}$ undergoes partial hydrolysis.

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Solution

A. 1.White phosphorous dissolves in boiling $N a O H$ solution in a atmospheric $C O_{2}$ , to give

Phosphine, $(P H_{3})$ .

2.The equation is $P_{4} + 3 N a O H + 3 H_{2} O - - - - - - > P H_{3} + 3 N a H_{2} P O_{2}$ .

B. When xenon hexaflouride undergoes partial hydrolysis it giving

$X e F_{6} + H_{2} O \to X e O F_{4} + 2 H F$

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What happens when i) White phosphorous is heated with concentrated NaOH solution in an inert atmosphere of CO2.ii) XeF6 undergoes partial hydrolysis.

A. 1.White phosphorous dissolves in boiling NaOH solution in a atmospheric CO2, to give Phosphine, (PH3). 2.The equation is P4+3NaOH+3H2O−−−−−−>PH3+3NaH2PO2. B. When xenon hexaflouride undergoes partial hydrolysis it giving XeF6+H2O→XeOF4+2HF

What happens when
i) White phosphorous is heated with concentrated $N a O H$ solution in an inert atmosphere of $C O_{2}$ .
ii) $X e F_{6}$ undergoes partial hydrolysis.