Question

What happens when Lead Nitrate reacts with Potassium Iodide?

Answer 1

Lead Nitrate with Potassium Iodide

• Lead(II) nitrate $\left(\mathrm{Pb}{\left({\mathrm{NO}}_3\right)}_2\right)$ interacts with potassium iodide $\left(\mathrm{KI}\right)$ to form Lead(II) iodide $\left({\mathrm{PbI}}_2\right)$ and Potassium nitrate $\left({\mathrm{KNO}}_3\right)$.
• This reaction can be considered a displacement reaction.

$2\mathrm{KI}\left(\mathrm{s}\right)+\mathrm{Pb}{\left({\mathrm{NO}}_3\right)}_2\left(\mathrm{aq}\right)\to 2{\mathrm{KNO}}_3\left(\mathrm{aq}\right)+{\mathrm{PbI}}_2\left(\mathrm{s}\right)$

Properties

• Potassium nitrate dissolves in water.
• Lead(II) iodide, on the other hand, is only moderately soluble in water.
• The majority of the lead(II) iodide in the solution precipitates out as a yellow solid.