What happens when magnesium is burnt in air and the products $X$ and $Y$ treated with water?

X - M g O, Y - M g (O H)_{2}, P - M g (O H)_{2}, Q - N_{2}

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X - M g O, Y - M g_{3} N_{2}, P - M g (O H)_{2}, Q - N H_{3}

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X - M g O, Y - M g_{3} N_{2}, P - M g (O H)_{2}, Q - N_{2}

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X - M g O, Y - M g C O_{3}, P - M g (O H)_{2}, Q - C O_{2}

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Solution

The correct option is B $X - M g O, Y - M g_{3} N_{2}, P - M g (O H)_{2}, Q - N H_{3}$
Magnesium reacts with air to form oxide and nitride. On reaction with water the oxide gives hydroxide and nitride gives hydroxide and ammonia.
$2 M g + O_{2} \to 2 M g O$
$3 M g + N_{2} \to M g_{3} N_{2}$
$M g O + H_{2} O \to M g (O H)_{2}$
$M g_{3} N_{2} + H_{2} O \to 3 M g (O H)_{2} + 2 N H_{3}$

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Similar questions

What will be the product of magnesium nitride $M g_{3} N_{2}$ with warm water?

What is the product formed when magnesium nitride, $M g_{3} N_{2}$ reacts with warm water?

H_{2} O

M g O, M g_{3} N_{2}

M g (O H)_{2}

N H_{3}

$M g O + H C l \to$ __________.

M g {(O H)}_{2}

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