Question

What happens when $NaB{H}_4$ is dissolved in water?

• A. It decomposes with the evolution of $H_2$
• B. $N{a}^{+}$ and $B{H}_4^{-}$ are formed, which are stable
• C. $B{H}_4^{-}$ ions formed initially, decompose to produce $O{H}^{-}$ ions, which prevent further decomposition
• D. $NaH$ and $B_2{H}_6$ are produced

Answer 1

The correct option is C $B{H}_4^{-}$ ions formed initially, decompose to produce $O{H}^{-}$ ions, which prevent further decomposition

Sodium borohydride is soluble in water, but it reacts with water. When dissolved in water, hydrogen gas is formed as a reaction by-product. Hydrogen gas is extremely flammable.

When sodium borohydride is dissolved in water, it decomposes to produce sodium hydroxide and hydrogen. Due to the formation of sodium hydroxide, further decomposition of sodium borohydride is prevented.

Hence, the correct option is $\text{C}$