What happens when $(N H_{4})_{2} C r_{2} O_{7}$ is heated?

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Solution

(I) $Z n + H_{2} {S O}_{4} ⟶ {Z n S O}_{4} + H_{2}$
(dil)
oxidizing agent $\to (H^{+})$
$∵ H^{+}$ gains electrons
(II) $Z n + H_{2} {S O}_{4} ⟶ {Z n S O}_{4} + {S O}_{2} + H_{2} O$
(conc)
oxidizing agent $\to {S O}_{4}^{2 -}$
$∵$ Sulphur gains electrons.

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