What happens when sulphur dioxide is passed through an aqueous solution of $F e (I I I)$ salt?

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Solution

$S O_{2}$ acts as a reducing agent and reduces an aqueous solution of $F e (I I I)$ salt to $F e (I I)$ salt, given by the equation.

$S O_{2} + 2 H_{2} O \to S O_{4}^{2 -} + 4 H^{+} + 2 e^{-}$

$2 F e^{3 +} + 2 e^{-} \to 2 F e^{2 +}$
$¯ ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ ¯ 2 F e^{3 +} + S O_{2} + 2 H_{2} O \to 2 F e^{2 +} + S O_{4}^{2 -} + 4 H^{+}$

This is indicated by the removal of green colour and formation of a light brown colour.

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