What happens when (write balanced chemical equations):
A mixture of methane and oxygen (in the volume ratio 9:1) is passed through a copper tube at $200 ° C$ and $100 atm$ .

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Solution

Step 1:
In an organic reaction, a reagent reacts with a reactant molecule to produce an intermediate which is converted into final products.
This reaction shows an oxidation reaction, different types of products are formed under different conditions like temperature, pressure, and catalyst.
The reaction of Methane $({CH}_{4})$ with Oxygen $(O_{2})$ in the presence of Copper $(Cu)$ tube at $200 ° C$ and $100 atm$ gives an oxidation reaction to produce Methanol $({CH}_{3} OH)$ .
Step 2:
The chemical reaction is given as:
$2 {CH}_{4} + O_{2} \overset{Cu - Tube}{\to} 2 {CH}_{3} OH Methane Oxygen Methanol$

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What happens when (write balanced chemical equations):A mixture of methane and oxygen (in the volume ratio 9:1) is passed through a copper tube at 200°C and 100atm.

What happens when (write balanced chemical equations):
A mixture of methane and oxygen (in the volume ratio 9:1) is passed through a copper tube at $200 ° C$ and $100 atm$ .