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Question

What hybridization is expected on the central atom of each of the following molecules ?
(i) BeH2
(ii) CH2Br2
(iii) PF−6
(iv) BF3

A
sp2,sp,sp3,sp2
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B
sp,sp3,sp3d,sp2
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C
sp,sp3,sp3d2,sp2
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D
sp2,sp,sp2,sp3
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Solution

The correct option is C sp,sp3,sp3d2,sp2
H=12[V+MC+A]
where,
H= Number of orbitals involved in hybridization.
V=Valence electrons of central atom.
M- Number of monovalent atoms linked to central atom.
C= Charge of cation.
A= Charge of anion.
Consider the hybridization of the options:-
A) BeH2-
H=12[2+2]=2.
sp hybridized state.
B) CH2Br2
H=12[4+4]=4.
sp3 hybridized state.
C) PF6
H=12[5+6+1]=6.
sp3d2 hybridized state.
D) BF3
H=12[3+3]=3.
sp2 hybridized state.
Hence option C is the right answer.

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