What is 18th terms of the sequence defined by an - nn - 3n - 4

We have, a_n = n(n 3)n + 4 Putting n = 18 , we get a_18 = 18 ×(18 3)18 + 4 = 18 × 1522 = 13511 . ...

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Sum of Infinite Terms of a GP

What is 18t...

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What is $18^{t h}$ terms of the sequence defined by $a_{n} = \frac{n (n - 3)}{n + 4}$

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a_{n} = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} n (n + 3), & i f n ϵ N and n is even \frac{2 n}{n^{2} + 1}, & i f n ϵ N and n is odd. \end{matrix}

a_{n} = \frac{n (n - 3)}{n + 4}

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a_{n} = \frac{n (n - 3)}{n + 4}

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