What is $a_{4}$ when $a_{1} = 2, r = - 3$ ?

27

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- 27

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- 54

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54

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Solution

The correct option is C $- 54$
Given, $a = 2$ , common ratio $= r = - 3$
We know the formula for $n^{t h}$ term,
$a_{n} = a r^{n - 1}$
$a_{4} = 2 \times (- 3)^{4 - 1}$
$= 2 \times - 3^{3}$
$= 2 \times (- 27)$
$= - 54$

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