The correct option is C Glucose-6-Phosphate
During glycolysis, the breakdown of the six-carbon glucose into two molecules of the three-carbon pyruvate occurs in ten steps, the first five of which constitute the preparatory phase. The energy gain comes in the second or payoff phase of glycolysis. In the preparatory phase of glycolysis, two molecules of ATP are invested and the hexose chain is cleaved into two triose phosphates. In the first step of glycolysis, glucose is activated for subsequent reactions by its phosphorylation at C-6 to yield glucose 6-phosphate, with ATP as the phosphoryl donor: This reaction, which is irreversible under intracellular conditions, is catalyzed by the enzyme hexokinase. The glucose molecule which is otherwise a stable molecule needs to be destabilised by addition of high energy phosphates in order to kick start its degradation and this purpose is served by hexokinase and later on phosphofructokinase enzyme in a subsequent reaction. The activated glucose Glucose 6 Phosphate is called active glucose. More the energy content in any molecule lesser will be its stability.