Question

What is an approximate value of $\sqrt{9805}$?

• A. 98.56
• B. 97.23
• C. 99.05
• D. 100.34

Answer 1

Answer: (C)

99.05

${99}^2$ = 9801
${100}^2$ = 10000
In between this two squares, 9805 is placed.
So the average of $\frac{99+100}{2}=99.5$
Then, ${99.5}^2=9900.25$
So, $\sqrt{9805}\approx 99.05$