What is approximately the centripetal acceleration (in units of acceleration due to gravity on earth, $g = 10 m s^{- 2})$ of an aircraft flying at a speed of 400 $m s^{- 1}$ through a circular arc of radius 0.6 km?

26.7

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16.9

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13.5

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30.2

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Solution

The correct option is D 26.7
Here, $v = 400 m s^{- 1}$ ,
$r = 0.6 k m = 0.6 \times 10^{3} m,$
$g = 10 m s^{- 2}$
Centripetal acceleration,
$a_{c} = \frac{v^{2}}{r} = \frac{(400 m s^{- 1})^{2}}{0.6 \times 10^{3} m}$
$= 26.7 \times 10 m s^{- 2}$
In the units of ( $g = 10 m s^{- 2}$ ), the centripetal acceleration is $26.7.$

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What is approximately the centripetal acceleration (in units of acceleration due to gravity on earth, g=10ms−2) of an aircraft flying at a speed of 400 ms−1 through a circular arc of radius 0.6 km?

The correct option is D 26.7Here,v=400ms−1,r=0.6km=0.6×103m,g=10ms−2Centripetal acceleration,ac=v2r=(400ms−1)20.6×103m=26.7×10ms−2In the units of (g=10ms−2), the centripetal acceleration is 26.7.

What is approximately the centripetal acceleration (in units of acceleration due to gravity on earth, $g = 10 m s^{- 2})$ of an aircraft flying at a speed of 400 $m s^{- 1}$ through a circular arc of radius 0.6 km?