Question

What is (are) true about the following reaction?

$C{H}_3-\stackrel{C{H}_3}{\stackrel{|}{C}H}-CH=C{H}_2+\underset{Majorproduct}{HBr\stackrel{ROOR}{\to }}$

• A. Reaction is initiated by the following step $R{O}^{\cdot }+HBr\to ROBr+H^{\cdot }$
• B. Major product is $2$-bromo-$2$-methyl butane
• C. In the first propagation step,a bromine atom attack to double bond forming a $2^{\circ }$ free radical
• D. The major product is a single achiral,bromoalkane

Answer 1

Answer: (C), (D)

The correct options are
C The major product is a single achiral,bromoalkane
D In the first propagation step,a bromine atom attack to double bond forming a $2^{\circ }$ free radical

$C{H}_3-CH-CH=C{H}_2+B{r}^{\bullet }⟶C{H}_3-\stackrel{C{H}_3}{\stackrel{|}{C}H}-\stackrel{\bullet }{C}H-C{H}_{2}Br\stackrel{HBr}{\to }\underset{\left(achiral\right)}{C{H}_3-\stackrel{C{H}_3}{\stackrel{|}{C}H}-C{H}_2}-C{H}_{2}Br$

So in the above reaction propagation step,a bromine atom attack to double bond forming a

2∘ free radical. The major product is a single achiral,bromoalkane

Hence options C & D are correct.