What is area of equilateral triangle?

\frac{3}{4} a^{2}

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\frac{\sqrt{3}}{4} a^{2}

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\frac{3 \sqrt{3}}{4} a^{2}

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\frac{a^{2}}{4}

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Solution

The correct option is B $\frac{\sqrt{3}}{4} a^{2}$
Area of an equilateral triangle with side $^{'} a^{'}$ units is

$A = \frac{\sqrt{3}}{4} a^{2}$ Sq.units

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Similar questions

In an equilateral triangle with side a, prove that area $= \frac{\sqrt{3}}{4} a^{2}$ .

a

\frac{\sqrt{3}}{4} a^{2}

a

A l t i t u d e = \frac{a \sqrt{3}}{2}

A r e a = \frac{\sqrt{3}}{4} a^{2}

\frac{\sqrt{3}}{4} a^{2}

(\frac{3}{4} a^{2} + 3 b^{2})

4 (a^{2} - \frac{2}{3} b^{2})

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