Question

What is best reagent would you choose to convert $Mn{O}_4^{2-}$ to $Mn{O}_4^{-}$?

• A. $C{l}_2$ water
• B. $O_3$
• C. Both $\left(A\right)$ and $\left(B\right)$
• D. None of these

Answer 1

The correct option is C Both $\left(A\right)$ and $\left(B\right)$

Solution:- (C) Both (A) and (B)

Oxidation state of $Mn$ in ${Mn{O}_4}^{-2}=+6$

Oxidation state of $Mn$ in ${Mn{O}_4}^{-}=+7$

$Mn$ is oxidising from $+6$ to $+7$. Since both ${Cl}_2$ water and $O_3$ are good reducing agent, thus both can be used.